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ANCHOR BOLT DESIGN Combined Tension and Shear
Result Summary                  
Anchor Rod Embedment, Spacing and Edge Distance       OK  
Overall         ratio = 0.70 OK  
Seismic Design         Tension =   OK  
          Shear =   OK  
Design Code Reference                  
Anchor bolt design based on                 Code Abbreviation
ACI 318-14 Building Code Requirements for Structural Concrete and Commentary ACI 318-14
PIP STE05121 Anchor Bolt Design Guide-2006 PIP STE05121
                Code Reference
Anchor Bolt Data                    
Factored tensile force Nu = [kips]      
Factored shear force Vu = [kips]      
Concrete strength f'c = [ksi]    
Anchor bolt material   =          
Anchor tensile strength futa = 58.0 [ksi]         ACI 318-14
      Anchor is ductile steel element       2.3 & 17.3.3 (a)
Anchor bolt diameter da  = [in]            
Anchor bolt has sleeve   =           PIP STE05121
                PIP STE05121
Anchor bolt edge distance c1 c1 = [in] 4.50   OK   Page A -1 Table 1
Anchor bolt edge distance c2 c2 = [in] 4.50   OK    
Anchor bolt edge distance c3 c3 = [in] 4.50   OK    
Anchor bolt edge distance c4 c4 = [in] 4.50   OK    
                   
Anchor bolt embedment depth hef = [in]         ACI 318-14
ci ≥ 1.5hef for at least two edges to avoid reducing of hef when Nu > 0   OK   17.4.2.3
Anchor bolt adjusted hef for design hef = [in] 12.00   OK   17.4.2.3
Concrete thickness ha = [in] 15.00   OK    
                   
Anchor bolt head type        
Anchor effective cross section area Ase = 0.606 [in2]        
Anchor bolt head bearing area Abrg = [in2]
         
Anchor bolt 1/8" (3mm) corrosion allowance =           ACI 318-14
Supplementary reinforcement                  
        For tension   = Condition A       17.3.3 (c)
        For shear Yc,v = Condition A       17.5.2.7
                  ACI 318-14
Provide built-up grout pad ?   =           17.5.1.3
Concrete cracking   =         17.4.2.6, 17.4.3.6, 17.5.2.7
                  ACI 318-14
Seismic design category SDC >= C   =           17.2.3.1
Anchor bolt load E <= 0.2U Tensile =   Shear =   17.2.3.4.1 & 17.2.3.5.1
Anchor bolt satisfies opion Tensile = Shear = 17.2.3.4.3 & 17.2.3.5.3
                   
Strength reduction factors                 ACI 318-14
Anchor reinforcement fs = 0.75           17.4.2.9 & 17.5.2.9
Anchor rod - ductile steel ft,s = 0.75   fv,s = 0.65   17.3.3 (a)
Concrete ft,c = 0.75  Cdn-A fv,c = 0.75  Cdn-A 17.3.3 (c)
CONCLUSION
                 
Anchor Rod Embedment, Spacing and Edge Distance       OK  
Overall ratio = 0.70 OK  
Tension          
Anchor Rod Tensile Resistance ratio = 0.38 OK  
Concrete Tensile Breakout Resistance ratio = 0.31 OK  
Anchor Pullout Resistance ratio = 0.31 OK  
Side Blowout Resistance ratio = 0.00 NA  
Shear          
Anchor Rod Shear Resistance ratio = 0.46 OK  
Concrete Shear Breakout Resistance - Perpendicular To Edge ratio = 0.24 OK  
Concrete Shear Breakout Resistance - Parallel To Edge ratio = 0.11 OK  
Concrete Pryout Shear Resistance ratio = 0.08 OK  
Tension Shear Interaction          
Tension Shear Interaction ratio = 0.70 OK  
           
Seismic Design         ACI 318-14
Tension Applicable       OK 17.2.3.4
Option A is satisfied, provided the conditions in 17.2.3.4.3(a) subsections 3~6, as applicable, are also met    
Seismic SDC>=C and E>0.2U , Option A is selected to satisfy additional seismic requirements as per 17.2.3.4.3    
                   
Shear Applicable       OK 17.2.3.5
Seismic SDC>=C and E>0.2U , Option C is selected to satisfy additional seismic requirements as per 17.2.3.5.3    
Assumptions ACI 318-14
1. Concrete is cracked 17.4.2.6, 17.4.3.6, 17.5.2.7
2. Condition A - supplementary reinforcement provided 17.3.3 (c)
3. Load combinations shall be per ACI 318-14 5.3.1 17.3.3
4. Tensile load acts through center of bolt group Yec,N =1.0 17.4.2.4
5. Shear load acts through center of bolt group Yec,V =1.0 17.5.2.5
CACULATION                  
Anchor Rod Tensile Resistance                 ACI 318-14
  f t,s Nsa = f t,s Ase futa = 26.36 [kips] 17.4.1.2 Eq 17.4.1.2
  ratio = 0.38 > Nu OK  
               
Concrete Tensile Breakout Resistance       ACI 318-14
  Nb = 24 l √fc hef1.5  if hef <11" or hef>25" = 72.57 [kips] 17.4.2.2 Eq 17.4.2.2a
      16 l √fc hef(5/3)  if 11"≤ hef ≤25"       17.4.2.2 Eq 17.4.2.2b
Projected conc failure area 1.5 hef =   = 18.00 [in]  
  ANC = [min(c1,1.5hef)+min(c3,1.5hef)]x = 1089.0 [in2]  
      [min(c2,1.5hef)+min(c4,1.5hef)]        
  ANCO = 9 hef2 = 1296.0 [in2] 17.4.2.1 Eq 17.4.2.1c
  ANC = min ( ANC, 1x ANCO ) = 1089.0 [in2] 17.4.2.1
Min edge distance cmin = min( c1, c2, c3, c4 ) = 15.00 [in]  
Eccentricity effects Ψec,N = 1.0  for no eccentric load       17.4.2.4
Edge effects Ψed,N = min[ (0.7+0.3cmin/1.5hef), 1.0 ] = 0.95   17.4.2.5
Concrete cracking Ψc,N = 1.00  for cracked concrete       17.4.2.6
Concrete splitting Ψcp,N = 1.00  for cast-in anchor       17.4.2.7
               
Concrete breakout resistance ftcNcbg =
ftc  ANC Ψec,N Ψed,N Ψc,N Ψcp,N Nb
ANCO
= 43.45 [kips] 17.4.2.1 Eq 17.4.2.1b
               
Seismic design strength reduction   = x 0.75 applicable = 32.59 [kips] 17.2.3.4.4
  ratio = 0.31 > Nu OK  
               
Anchor Pullout Resistance             ACI 318-14
Single bolt pullout resistance N p = 8 Abrg fc' = 62.44 [kips] 17.4.3.4 Eq 17.4.3.4
  ft,c Npn = f t,c  Ψc,p Np = 43.71 [kips] 17.4.3.1 Eq 17.4.3.1
  Ψc,p = 1.00  for cracked concrete       17.4.3.6
  f t,c = 0.70 pullout strength is always Condition B 17.3.3(c)
Seismic design strength reduction   = x 0.75 applicable = 32.78 [kips] 17.2.3.4.4
  ratio = 0.31 > Nu OK  
               
Side Blowout Resistance              
  c = min ( c1, c2, c3, c4 ) = 15.00 [in]  
Check if side blowout applicable hef = 12.00 [in]         ACI 318-14  
    < 2.5c side bowout is NOT applicable 17.4.4.1
Single anchor SB resistance ft,c Nsb = = 0.00 [kips] 17.4.4.1 Eq 17.4.4.1
Edge reduction factor   = ( 1+ ca2 / ca1 ) / 4 = 0.50   17.4.4.1
SB resistance after edge reduction ftcNsb =  ft,c Nsb x [1+ca2 / ca1] / 4 = 0.00 [kips] 17.4.4.1
Seismic design strength reduction   = x 0.75 applicable = 0.00 [kips] 17.2.3.4.4
  ratio = 0.00 Nu NA  
               
Govern Tensile Resistance Nr = min ( f Nsa, f Ncb, f Npn, f Nsb ) =  26.36 [kips]  
               
Anchor Rod Shear Resistance             ACI 318-14
  f v,sVsa = f v,s 0.6 Ase futa = 13.71 [kips] 17.5.1.2 (b)
Reduction due to built-up grout pad   = x 0.8 , applicable = 10.97 [kips] 17.5.1.3
  ratio = 0.46 > Vu OK  
               
Conc. Shear Breakout Resistance - Perpendicular To Edge        
               
 
               
Bolt edge distance ca1 = c1 = 15.00 [in] ACI 318-14
Limiting ca1 when anchors are influenced by 3 or more edges = No   17.5.2.4
Bolt edge distance - adjusted ca1 = ca1 needs NOT to be adjusted = 15.00 [in] 17.5.2.4
  1.5ca1 =   = 22.50 [in] ACI 318-14
  Avc = [min(c2,1.5ca1)+ s2 +min(c4,1.5ca1)]x = 562.5 [in2] 17.5.2.1
      min(1.5ca1, ha)       ACI 318-14
  Avco = 4.5ca12 = 1012.5 [in2] 17.5.2.1 Eq 17.5.2.1c
  Avc = min ( Avc, 1x Avco ) = 562.5 [in2] 17.5.2.1
  le = min( 8da , hef ) = 8.00 [in] 17.5.2.2
  Vb1 = = 44.45 [kips] 17.5.2.2 Eq 17.5.2.2a
  Vb2 = = 37.70 [kips] 17.5.2.2 Eq 17.5.2.2b
  Vb = min( Vb1 , Vb2 ) = 37.70 [kips] 17.5.2.2
Eccentricity effects Ψec,v = 1.0 shear acts through center of group       17.5.2.5
Edge effects Ψed,v = min[ (0.7+0.3c2/1.5c1), 1.0 ] = 0.90   17.5.2.6
Concrete cracking Ψc,v = concrete is cracked = 1.20   17.5.2.7
Member thickness Ψh,v = max[ (sqrt(1.5c1 / ha) , 1.0 ] = 1.22   17.5.2.8
              ACI 318-14
Conc shear breakout resistance Vcb =
fv,c  Avc Ψec,v Ψed,v Ψc,v Ψh,v Vb
Avco
= 20.78 [kips] 17.5.2.1 Eq 17.5.2.1b
- perpendicular to edge              
  ratio = 0.24 > Vu OK  
               
Conc. Shear Breakout Resistance - Parallel To Edge        
               
Bolt edge distance ca1 = min(c2 , c4) = 15.00 [in] ACI 318-14
Limiting ca1 when anchors are influenced by 3 or more edges = No   17.5.2.4
Bolt edge distance - adjusted ca1 = ca1 needs NOT to be adjusted = 15.00 [in] 17.5.2.4
  1.5ca1 =   = 22.50 [in] ACI 318-14
  Avc = [min(c1,1.5ca1) + s1+ min(c3,1.5ca1)]x = 562.5 [in2] 17.5.2.1
      min(1.5ca1, ha)       ACI 318-14
  Avco = 4.5ca12 = 1012.5 [in2] 17.5.2.1 Eq 17.5.2.1c
  Avc = min ( Avc, nbd Avco ) = 562.5 [in2] 17.5.2.1
  le = min( 8da , hef ) = 8.00 [in] 17.5.2.2
  Vb1 = = 44.45 [kips] 17.5.2.2 Eq 17.5.2.2a
  Vb2 = = 37.70 [kips] 17.5.2.2 Eq 17.5.2.2b
  Vb = min( Vb1 , Vb2 ) = 37.70 [kips] 17.5.2.2
Eccentricity effects Ψec,v = 1.0 shear acts through center of group       17.5.2.5
Edge effects Ψed,v =   = 1.00   17.5.2.1 (c)
Concrete cracking Ψc,v = concrete is cracked = 1.20   17.5.2.7
Member thickness Ψh,v = max[ (sqrt(1.5ca1 / ha) , 1.0 ] = 1.22   17.5.2.8
              ACI 318-14
Conc shear breakout resistance Vcb-p =
2xfv,c  Avc Ψec,v Ψed,v Ψc,v Ψh,v Vb
Avco
= 46.18 [kips] 17.5.2.1 Eq 17.5.2.1b
- parallel to edge             17.5.2.1 (c)
  ratio = 0.11 > Vu OK  
               
Conc. Pryout Shear Resistance             ACI 318-14
  kcp = 2.0       17.5.3.1
Factored shear pryout resistance fv,cVcp = fv,c kcp Ncb = 81.10 [kips] 17.5.3.1 Eq 17.5.3.1b
  f v,c = 0.7  pryout strength is always Condition B   17.3.3 (c)
               
Seismic design strength reduction   = x 0.75 applicable = 60.83 [kips] 17.2.3.4.4
  ratio = 0.08 > Vu OK  
               
Govern Shear Resistance Vr = min ( fVsa , fVcb , fVcb-p , fVcp ) = 10.97 [kips]  
               
Tension Shear Interaction             ACI 318-14
Check if Nu >0.2f Nn and Vu >0.2f Vn = Yes       17.6.1 & 17.6.2
      Nu / f Nn + Vu / f Vn = 0.84   17.6.3 Eq 17.6.3
  ratio = 0.70 < 1.2 OK  
               
Seismic Design              
Tension     Applicable     OK  
Option A is selected. ACI 318-14
The program will flag OK if 17.2.3.4.3(a) subsections 1 & 2 are met and the ductile anchor steel strength
has the highest utilization ratio.  User has to verify the conditions in 17.2.3.4.3(a) subsections 3~6, as applicable, are met. 		17.2.3.4.3(a)
               
Steel nominal strength x 1.2 1.2Nsa = 42.18 [kips]          
Conc governed nominal strength Ncb = 57.93 [kips] Npn = 62.44 [kips]  
   Nsb = 0.00 [kips]          
Nu / min( Ncb , Npn , Nsb ) = 0.17   Nu / 1.2Nsa = 0.24    
          > 0.17 OK  
                   
Option A is satisfied, provided the conditions in 17.2.3.4.3(a) subsections 3~6, as applicable, are also met    
                   
Seismic SDC>=C and E>0.2U , Option A is selected to satisfy additional seismic requirements as per 17.2.3.4.3    
               
Shear     Applicable     OK  
Option C is selected.             ACI 318-14
User has to ensure that the shear load Vu user input above includes the seismic load E, with E increased
by multiplying overstrength factor Ωo 		17.2.3.5.3(c)
               
Seismic SDC>=C and E>0.2U , Option C is selected to satisfy additional seismic requirements as per 17.2.3.5.3    
                   

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